/* Write a C program to accept a decimal number and conert it binary and count the number of 1's in the binary number */
#include <stdio.h>
void main()
{
long num, dnum, rem, base = 1, bin = 0, no_of_1s = 0;
printf("Enter a decimal integer\n");
scanf("%ld", &num);
dnum = num;
while( num > 0 )
{
rem = num % 2;
if ( rem == 1 ) /*To count no.of 1s*/
{
no_of_1s++;
}
bin = bin + rem * base;
num = num / 2 ;
base = base * 10;
}
printf("Input number is = %d\n", dnum);
printf("Its Binary equivalent is = %ld\n", bin);
printf("No.of 1's in the binary number is = %d\n", no_of_1s);
} /* End of main() */
/*--------------------------------------------------
Output
Enter a decimal integer
75
Input number is = 75
Its Binary equivalent is = 1001011
No.of 1's in the binary number is = 4
RUN2
Enter a decimal integer
128
Input number is = 128
Its Binary equivalent is = 10000000
No.of 1's in the binary number is = 1
-----------------------------------------------------*/
#include <stdio.h>
void main()
{
long num, dnum, rem, base = 1, bin = 0, no_of_1s = 0;
printf("Enter a decimal integer\n");
scanf("%ld", &num);
dnum = num;
while( num > 0 )
{
rem = num % 2;
if ( rem == 1 ) /*To count no.of 1s*/
{
no_of_1s++;
}
bin = bin + rem * base;
num = num / 2 ;
base = base * 10;
}
printf("Input number is = %d\n", dnum);
printf("Its Binary equivalent is = %ld\n", bin);
printf("No.of 1's in the binary number is = %d\n", no_of_1s);
} /* End of main() */
/*--------------------------------------------------
Output
Enter a decimal integer
75
Input number is = 75
Its Binary equivalent is = 1001011
No.of 1's in the binary number is = 4
RUN2
Enter a decimal integer
128
Input number is = 128
Its Binary equivalent is = 10000000
No.of 1's in the binary number is = 1
-----------------------------------------------------*/
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