/* Write a C program to evaluate the equation y=xn when n is a non-negative integer. */
=================================================================
#include<stdio.h>
#include<conio.h>
void main()
{
int count, n;
float x,y;
printf(“Enter the values of x and n:”);
scanf(“%f%d”, &x,&n);
y=1.0;
count=1;
while(count<=n)
{
y=y*x;
count++;
}
printf(“x=%f; n=%d; x to power n=%f”, x, n,y);
}
Output:
======
Enter the values of x and n: 2.5 4
X=2.500000; n=4; x to power n= 39.062500
=================================================================
#include<stdio.h>
#include<conio.h>
void main()
{
int count, n;
float x,y;
printf(“Enter the values of x and n:”);
scanf(“%f%d”, &x,&n);
y=1.0;
count=1;
while(count<=n)
{
y=y*x;
count++;
}
printf(“x=%f; n=%d; x to power n=%f”, x, n,y);
}
Output:
======
Enter the values of x and n: 2.5 4
X=2.500000; n=4; x to power n= 39.062500
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